John Errington's Data Conversion Website
Sampling rate
The choice of sampling rate is determined from the highest frequency present in significant amount in the signal. For audio signals we may have frequencies to above 50kHz, but only want to respond to 20kHz and below. In this case filtering would be needed to remove these high frequencies beofre sampling takes place. The strategy chosen determines the number of samples taken during 1 period of the highest frequency present in the signal.
( The period is the time taken for 1 full cycle of a repetitive wave. The envelope modulation approach gives useful sampling rates with good accuracy for most applications. Also referred to as oversampling.
Strategy  no of samples per period  samples per period for 8 bit converter  Explanation 
Every reading precise  * 2 n  800  Used for nonrepetitive signals where extreme precision is required 
Nyquist criterion  2  2  Used for very repetitive signals; lower limit of sampling rate 
Envelope modulation  exp 0.374 n  20  Chosen to match sampling error to resolution or measurement error inherent in converter 
Here you can see the effects of sampling a sine wave at different rates.
This graph shows a sine wave generated using 25 samples per cycle. This corresponds to 12 times oversampling, and approximately matches the envelope modulation criterion. You can see that within one cycle both the shape and amplitude of the wave are very well defined.


Here you can see the sine wave generated above being sampled at around 8 samples per period. If you look at the second wave you will see there are no samples at the peak. So within one wave this sampling rate does not guarantee an accurate measure of the amplitude. However the frequency of the wave is quite clearly defined. 

This graph shows the effect of sampling at just over two samples per period. This is the Nyquist rate, the lowest sampling rate at which the wave will be correctly represented. You can see that it is not possible to measure either the wave frequency or amplitude with any degree of accuracy before a few cycles of the wave have elapsed. However during the course of a few cycles we can build up a fairly clear picture of the amplitude and frequency of the wave. The Nyquist criterion gives us the bare minimum information and is only useful for observing signals that repeat many times without changing much. 

Here you see the effect of sampling at less than the Nyquist rate. Not only do we not get an accurate picture of the amplitude, but the results give us a completely inaccurate idea of the signal frequency. This is the real value of the Nyquist theorem in showing there are sampling rates which will give us false information. 
Every reading precise
If each reading must be accurate to the precision of the converter, then the input signal may not change by more than one resolution interval q during the time t taken for the measurement. We can represent this as dv/dt < q / t.
A sine wave matched to the full scale range of the converter can be represented as v = ( FSR/2 ) sin 2 f t
by differentiating dv/dt = 2 f (FSR/2) cos 2 f t
and dv/dt (max) = 2 f (FSR/2) as max value of cos = +/ 1
now q = FSR / 2n
so at the limit 2 f (FSR / 2) = ( FSR / 2n ) / t f = 1 / 2n t
if we let f =1 / T where T is the period of the sampled wave, then we get T = 2n t
showing we need 2n samples per period. This is 800 samples per period for an 8 bit converter!
Nyquist criterion ( sampling theorem)
The information present in a signal can be recovered by taking at least 2 samples in every period of the highest frequency present in the wave, over a large number of periods.
Envelope modulation analysis
When we sample a wave we multiply the incoming wave by a sampling wave with a value of 1 at the sample points and 0 elsewhere. Signal processing theory allows us to write an expression for the sampled wave.
If we sample a signal v = f ( t ) at regular intervals ts using a converter that takes a time tc for conversion, the signal is modified by a factor
Venv ( f ) = 2 ( tc / ts ) * ( ( sin tc f ) / ( tc f ) )
This results in a measurement error V / Vpeak = 1  ( ( sin tc f ) / ( tc f ) )
we can expand sin(x) using the MacLaurin expansion sin( x ) = x/1!  x3/3! + x5 /5!  ..,
whence sin( x ) / x = 1/1!  x2/3! + x4 / 5!  x6/7! + ...
V / Vpeak = ( tc f )2 / 3!  ( tc f )4 / 5! + ( tc f )6 / 7!
By substituting in values we can show that for a converter with a conversion time of 50 microseconds, and a wave frequency of 1kHz (giving 20 samples per period) we get a measurement error of 0.41%. This is comparable with the measurement accuracy of an 8 bit converter.
If we let the period of the wave be T = 1 / f
V / Vpeak = ( tc / T )2 / 3!  ( tc / T )4 / 5! + ( tc / T )6 / 7! and if tc / T < 0.1 we can ignore higher terms, and error is given by
measurement error = V / Vpeak = ( tc / T )2 / 3! approximately, where tc / T = 1 / samples per period.
The chart that follows shows the measurement error for different sampling ratios.
converter resolution for n bits  
n bits  levels  resolution, % of FSR 
1  2  50 
2  4  25 
3  8  12.500 
4  16  6.2500 
5  32  3.1250 
6  64  1.5625 
7  128  0.78125 
8  256  0.390 
9  512  0.195 
10  1024  0.098 
11  2048  0.0489 
12  4096  0.024 
13  8192  0.012 
14  16384  0.0061 
15  32768  0.0030 
16  65536  0.0015 